比较C＃中的两个XmlNode

Question

Is there a simple way to compare two XML structures to determine if they have the same structure and data?

I have a function that returns an XmlNode and I am trying to write unit tests for it. I store the correct XML result in a file. Durring the test I load the file into an XmlDocument, locate the proper XmlNode and compare against the result of the function. A straight compare does not work (as expected) and InnerXml does not work either. I am considering removing all whitespace from InnerXml and comparing that, or writing my own compare to walk the tree, but I don't like either option much.

Answer 1

XNode.DeepEquals . Read the caveats before using it.

Answer 2

Like CodeToGlory answered, XNode.DeepEquals() might fit your bill, check the remarks section on the MSDN page.

If you are stuck with XmlDocument (instead of XDocument), the answer is: No, there is no simple (existing way) to do it. XmlNode does not override Equals(), or provide an alternative. But it is not impossible to write, and that same Remarks section can be used as a starting point for a tree-walk algorithm.

Do get a clear picture of your requirements first, concerning Attributes, comments, CDATA nodes etc.

Answer 3

如果必须使用XmlDocument及其支持类型，请考虑使用Microsoft的XmlDiffPatch ，它在XML数据结构上执行可自定义的diff操作。