Console.WriteLine为十六进制

Question

The following code prints out 10 . How can I make it print out a ?

int i = 10;
Console.WriteLine("{0}", i);

Answer 1

Console.WriteLine ("Hex: {0:X}", nNum);

The X formatter outputs uppercase hex chars. Use a lowercase x for lowercase hex chars.

Answer 2

i.ToString（ “X”）;

Answer 3

int i=10;

Console.WriteLine("{0:x}", i);

or if you want 'A':

int i=10;

Console.WriteLine("{0:X}", i);

Answer 4

您需要添加格式说明符：

Console.WriteLine("{0:x}", i);

Answer 5

将格式更改为{0:x} 。

Answer 6

int i=10;
Console.WriteLine("{0:X4}", i);

Outputs hex with a size specifier.

you can also use string interpolation

int i=10;
Console.WriteLine($"{i:X4}");

Answer 7

Int32 num = 1024;

Basic Hex Formatting

Using string interpolation:
Console.WriteLine("{0:X}", num);

Using built-in numeric string formatting:
Console.WriteLine(num.ToString("X"));

400

Fixed Precision Hex Formatting

Console.WriteLine(num.ToString("X4"));

0400

or

Console.WriteLine("0x{0:x8}", num);

0x00000400