SQL“选择子查询中没有的地方”不返回任何结果

Question

Disclaimer: I have figured out the problem (I think), but I wanted to add this issue to Stack Overflow since I couldn't (easily) find it anywhere. Also, someone might have a better answer than I do.

I have a database where one table "Common" is referenced by several other tables. I wanted to see what records in the Common table were orphaned (ie, had no references from any of the other tables).

I ran this query:

select *
from Common
where common_id not in (select common_id from Table1)
and common_id not in (select common_id from Table2)

I know that there are orphaned records, but no records were returned. Why not?

(This is SQL Server, if it matters.)

Answer 1

Update:

These articles in my blog describe the differences between the methods in more detail:

• NOT IN vs. NOT EXISTS vs. LEFT JOIN / IS NULL : SQL Server
• NOT IN vs. NOT EXISTS vs. LEFT JOIN / IS NULL : PostgreSQL
• NOT IN vs. NOT EXISTS vs. LEFT JOIN / IS NULL : Oracle
• NOT IN vs. NOT EXISTS vs. LEFT JOIN / IS NULL : MySQL

---

There are three ways to do such a query:

• LEFT JOIN / IS NULL :

   SELECT * FROM common LEFT JOIN table1 t1 ON t1.common_id = common.common_id WHERE t1.common_id IS NULL

• NOT EXISTS :

   SELECT * FROM common WHERE NOT EXISTS ( SELECT NULL FROM table1 t1 WHERE t1.common_id = common.common_id )

• NOT IN :

   SELECT * FROM common WHERE common_id NOT IN ( SELECT common_id FROM table1 t1 )

When table1.common_id is not nullable, all these queries are semantically the same.

When it is nullable, NOT IN is different, since IN (and, therefore, NOT IN ) return NULL when a value does not match anything in a list containing a NULL .

This may be confusing but may become more obvious if we recall the alternate syntax for this:

common_id = ANY
(
SELECT  common_id
FROM    table1 t1
)

The result of this condition is a boolean product of all comparisons within the list. Of course, a single NULL value yields the NULL result which renders the whole result NULL too.

We never cannot say definitely that common_id is not equal to anything from this list, since at least one of the values is NULL .

Suppose we have these data:

common

--
1
3

table1

--
NULL
1
2

LEFT JOIN / IS NULL and NOT EXISTS will return 3 , NOT IN will return nothing (since it will always evaluate to either FALSE or NULL ).

In MySQL , in case on non-nullable column, LEFT JOIN / IS NULL and NOT IN are a little bit (several percent) more efficient than NOT EXISTS . If the column is nullable, NOT EXISTS is the most efficient (again, not much).

In Oracle , all three queries yield same plans (an ANTI JOIN ).

In SQL Server , NOT IN / NOT EXISTS are more efficient, since LEFT JOIN / IS NULL cannot be optimized to an ANTI JOIN by its optimizer.

In PostgreSQL , LEFT JOIN / IS NULL and NOT EXISTS are more efficient than NOT IN , sine they are optimized to an Anti Join , while NOT IN uses hashed subplan (or even a plain subplan if the subquery is too large to hash)

Answer 2

If you want the world to be a two-valued boolean place, you must prevent the null (third value) case yourself.

Don't write IN clauses that allow nulls in the list side. Filter them out!

common_id not in
(
  select common_id from Table1
  where common_id is not null
)

Answer 3

Table1 or Table2 has some null values for common_id. Use this query instead:

select *
from Common
where common_id not in (select common_id from Table1 where common_id is not null)
and common_id not in (select common_id from Table2 where common_id is not null)

Answer 4

The short answer:

There is a NULL within the collection returned by your subquery. You can solve the problem by removing that NULL value before finishing the subquery or to use NOT EXISTS predicate instead of NOT IT , as it does it implicitly.

The long answer (From T-SQL Fundamentals, Third edition, by Itzik Ben-Gan)

This is an example: Imagine there is a order with a NULL orderid inside Sales.Orders table , so the subquery returns some integers, and a NULL value.

SELECT custid, companyname
FROM Sales.Customers
WHERE custid NOT IN(SELECT O.custid
             FROM Sales.Orders AS O);

The explanation on why the query from above returns an empty set:

Obviously, the culprit here is the NULL customer ID you added to the Orders table. The NULL is one of the elements returned by the subquery. Let's start with the part that does behave like you expect it to. The IN predicate returns TRUE for a customer who placed orders (for example, customer 85), because such a customer is returned by the subquery. The NOT operator negates the IN predicate; hence, the NOT TRUE becomes FALSE , and the customer is discarded. The expected behavior here is that if a customer ID is known to appear in the Orders table, you know with certainty that you do not want to return it.

However (take a deep breath), if a customer ID from Customers doesn't appear in the set of non-NULL customer IDs in Orders, and there's also a NULL customer ID in Orders, you can't tell with certainty that the customer is there—and similarly you can't tell with certainty that it's not there. Confused? I hope I can clarify this explanation with an example.

The IN predicate returns UNKNOWN for a customer such as 22 that does not appear in the set of known customer IDs in Orders. That's because when you compare it with known customer IDs you get FALSE, and when you compare it with a NULL you get UNKNOWN . FALSE OR UNKNOWN yields UNKNOWN . Consider the expression 22 NOT IN (1, 2, <other non-22 values>, NULL) . This expression can be rephrased as NOT 22 IN (1, 2, …, NULL) . You can expand this expression to NOT (22 = 1 OR 22 = 2 OR … OR 22 = NULL) . Evaluate each individual expression in the parentheses to its truth value and you get NOT (FALSE OR FALSE OR … OR UNKNOWN) , which translates to NOT UNKNOWN , which evaluates to UNKNOWN .

The logical meaning of UNKNOWN here, before you apply the NOT operator, is that it can't be determined whether the customer ID appears in the set, because the NULL could represent that customer ID. The tricky part here is that negating the UNKNOWN with the NOT operator still yields UNKNOWN . This means that in a case where it is unknown whether a customer ID appears in a set, it is also unknown whether it doesn't appear in the set. Remember that a query filter discards rows that get UNKNOWN in the result of the predicate.

In short, when you use the NOT IN predicate against a subquery that returns at least one NULL , the query always returns an empty set. So, what practices can you follow to avoid such trouble? First, when a column is not supposed to allow NULLs , be sure to define it as NOT NULL . Second, in all queries you write, you should consider NULLs and the three-valued logic. Think explicitly about whether the query might process NULLs, and if so, whether SQL's treatment of NULLs is correct for you. When it isn't, you need to intervene. For example, our query returns an empty set because of the comparison with the NULL . If you want to check whether a customer ID appears only in the set of known values, you should exclude the NULLs—either explicitly or implicitly. To exclude them explicitly, add the predicate O.custid IS NOT NULL to the subquery, like this:

SELECT custid, companyname
FROM Sales.Customers
WHERE custid NOT IN(SELECT O.custid
                    FROM Sales.Orders AS O
                    WHERE O.custid IS NOT NULL);

You can also exclude the NULLs implicitly by using the NOT EXISTS predicate instead of NOT IN , like this:

SELECT custid, companyname
FROM Sales.Customers AS C
WHERE NOT EXISTS
   (SELECT *
    FROM Sales.Orders AS O
    WHERE O.custid = C.custid);

Recall that unlike IN , EXISTS uses two-valued predicate logic. EXISTS always returns TRUE or FALSE and never UNKNOWN . When the subquery stumbles into a NULL in O.custid , the expression evaluates to UNKNOWN and the row is filtered out. As far as the EXISTS predicate is concerned, the NULL cases are eliminated naturally, as though they weren't there. So EXISTS ends up handling only known customer IDs. Therefore, it's safer to use NOT EXISTS than NOT IN .

The information above is taken from Chapter 4 - Subqueries, T-SQL Fundamentals, Third edition

Answer 5

Just off the top of my head...

select c.commonID, t1.commonID, t2.commonID
from Common c
     left outer join Table1 t1 on t1.commonID = c.commonID
     left outer join Table2 t2 on t2.commonID = c.commonID
where t1.commonID is null 
     and t2.commonID is null

I ran a few tests and here were my results wrt @patmortech's answer and @rexem's comments.

If either Table1 or Table2 is not indexed on commonID, you get a table scan but @patmortech's query is still twice as fast (for a 100K row master table).

If neither are indexed on commonID, you get two table scans and the difference is negligible.

If both are indexed on commonID, the "not exists" query runs in 1/3 the time.

Answer 6

select *
from Common c
where not exists (select t1.commonid from table1 t1 where t1.commonid = c.commonid)
and not exists (select t2.commonid from table2 t2 where t2.commonid = c.commonid)

Answer 7

SELECT T.common_id
  FROM Common T
       LEFT JOIN Table1 T1 ON T.common_id = T1.common_id
       LEFT JOIN Table2 T2 ON T.common_id = T2.common_id
 WHERE T1.common_id IS NULL
   AND T2.common_id IS NULL

Answer 8

Let's suppose these values for common_id:

Common - 1
Table1 - 2
Table2 - 3, null

We want the row in Common to return, because it doesn't exist in any of the other tables. However, the null throws in a monkey wrench.

With those values, the query is equivalent to:

select *
from Common
where 1 not in (2)
and 1 not in (3, null)

That is equivalent to:

select *
from Common
where not (1=2)
and not (1=3 or 1=null)

This is where the problem starts. When comparing with a null, the answer is unknown . So the query reduces to

select *
from Common
where not (false)
and not (false or unkown)

false or unknown is unknown:

select *
from Common
where true
and not (unknown)

true and not unkown is also unkown:

select *
from Common
where unknown

The where condition does not return records where the result is unkown, so we get no records back.

One way to deal with this is to use the exists operator rather than in. Exists never returns unkown because it operates on rows rather than columns. (A row either exists or it doesn't; none of this null ambiguity at the row level!)

select *
from Common
where not exists (select common_id from Table1 where common_id = Common.common_id)
and not exists (select common_id from Table2 where common_id = Common.common_id)

Answer 9

this worked for me :)

select * from Common

where

common_id not in (select ISNULL(common_id,'dummy-data') from Table1)

and common_id not in (select ISNULL(common_id,'dummy-data') from Table2)

Answer 10

Please follow the below example to understand the above topic:

Also you can visit the following link to know Anti join

select department_name,department_id from hr.departments dep
where not exists 
    (select 1 from hr.employees emp
    where emp.department_id=dep.department_id
    )
order by dep.department_name;

DEPARTMENT_NAME DEPARTMENT_ID
Benefits    160
Construction    180
Contracting 190
.......

But if we use NOT IN in that case we do not get any data.

select Department_name,department_id from hr.departments dep 
where department_id not in (select department_id from hr.employees );

no data found

This is happening as ( select department_id from hr.employees ) is returning a null value and the entire query is evaluated as false. We can see it if we change the SQL slightly like below and handle null values with NVL function.

select Department_name,department_id from hr.departments dep 
where department_id not in (select NVL(department_id,0) from hr.employees )

Now we are getting data:

DEPARTMENT_NAME DEPARTMENT_ID
Treasury    120
Corporate Tax   130
Control And Credit  140
Shareholder Services    150
Benefits    160
....

Again we are getting data as we have handled the null value with NVL function.

Answer 11

select *,
(select COUNT(ID)  from ProductMaster where ProductMaster.CatID = CategoryMaster.ID) as coun 
from CategoryMaster

Answer 12

I had an example where I was looking up and because one table held the value as a double, the other as a string, they would not match (or not match without a cast). But only NOT IN . As SELECT ... IN ... worked. Weird, but thought I would share in case anyone else encounters this simple fix.