如何使用 PHP 从完整路径中获取文件名？

Question

For example, how do I get Output.map

from

F:\\Program Files\\SSH Communications Security\\SSH Secure Shell\\Output.map

with PHP?

Answer 1

You're looking for basename .

The example from the PHP manual:

<?php
$path = "/home/httpd/html/index.php";
$file = basename($path);         // $file is set to "index.php"
$file = basename($path, ".php"); // $file is set to "index"
?>

Answer 2

I've done this using the function PATHINFO which creates an array with the parts of the path for you to use! For example, you can do this:

<?php
    $xmlFile = pathinfo('/usr/admin/config/test.xml');

    function filePathParts($arg1) {
        echo $arg1['dirname'], "\n";
        echo $arg1['basename'], "\n";
        echo $arg1['extension'], "\n";
        echo $arg1['filename'], "\n";
    }

    filePathParts($xmlFile);
?>

This will return:

/usr/admin/config
test.xml
xml
test

The use of this function has been available since PHP 5.2.0!

Then you can manipulate all the parts as you need. For example, to use the full path, you can do this:

$fullPath = $xmlFile['dirname'] . '/' . $xmlFile['basename'];

Answer 3

There are several ways to get the file name and extension. You can use the following one which is easy to use.

$url = 'http://www.nepaltraveldoor.com/images/trekking/nepal/annapurna-region/Annapurna-region-trekking.jpg';
$file = file_get_contents($url); // To get file
$name = basename($url); // To get file name
$ext = pathinfo($url, PATHINFO_EXTENSION); // To get extension
$name2 =pathinfo($url, PATHINFO_FILENAME); // File name without extension

Answer 4

With SplFileInfo :

SplFileInfo The SplFileInfo class offers a high-level object oriented interface to information for an individual file.

Ref : http://php.net/manual/en/splfileinfo.getfilename.php

$info = new SplFileInfo('/path/to/foo.txt');
var_dump($info->getFilename());

o/p: string(7) "foo.txt"

Answer 5

The basename function should give you what you want:

Given a string containing a path to a file, this function will return the base name of the file.

For instance, quoting the manual's page:

<?php
    $path = "/home/httpd/html/index.php";
    $file = basename($path);         // $file is set to "index.php"
    $file = basename($path, ".php"); // $file is set to "index"
?>

Or, in your case:

$full = 'F:\Program Files\SSH Communications Security\SSH Secure Shell\Output.map';
var_dump(basename($full));

You'll get:

string(10) "Output.map"

Answer 6

试试这个：

echo basename($_SERVER["SCRIPT_FILENAME"], '.php') 

Answer 7

basename() has a bug when processing Asian characters like Chinese.

I use this:

function get_basename($filename)
{
    return preg_replace('/^.+[\\\\\\/]/', '', $filename);
}

Answer 8

$filename = basename($path);

Answer 9

您可以使用basename()函数。

Answer 10

To do this in the fewest lines I would suggest using the built-in DIRECTORY_SEPARATOR constant along with explode(delimiter, string) to separate the path into parts and then simply pluck off the last element in the provided array.

Example:

$path = 'F:\Program Files\SSH Communications Security\SSH SecureShell\Output.map'

//Get filename from path
$pathArr = explode(DIRECTORY_SEPARATOR, $path);
$filename = end($pathArr);

echo $filename;
>> 'Output.map'

Answer 11

To get the exact file name from the URI, I would use this method:

<?php
    $file1 =basename("http://localhost/eFEIS/agency_application_form.php?formid=1&task=edit") ;

    //basename($_SERVER['REQUEST_URI']); // Or use this to get the URI dynamically.

    echo $basename = substr($file1, 0, strpos($file1, '?'));
?>

Answer 12

Basename does not work for me. I got the filename from a form (file). In Google Chrome (Mac OS X v10.7 (Lion)) the file variable becomes:

c:\fakepath\file.txt

When I use:

basename($_GET['file'])

it returns:

c:\fakepath\file.txt

So in this case the Sun Junwen answer works best.

On Firefox the file's variable does not include this fakepath.

Answer 13

$image_path = "F:\Program Files\SSH Communications Security\SSH Secure Shell\Output.map";
$arr = explode('\\',$image_path);
$name = end($arr);

Answer 14

It's simple. For example:

<?php
    function filePath($filePath)
    {
        $fileParts = pathinfo($filePath);

        if (!isset($fileParts['filename']))
        {
            $fileParts['filename'] = substr($fileParts['basename'], 0, strrpos($fileParts['basename'], '.'));
        }
        return $fileParts;
    }

    $filePath = filePath('/www/htdocs/index.html');
    print_r($filePath);
?>

The output will be:

Array
(
    [dirname] => /www/htdocs
    [basename] => index.html
    [extension] => html
    [filename] => index
)

Answer 15

<?php

  $windows = "F:\Program Files\SSH Communications Security\SSH Secure Shell\Output.map";

  /* str_replace(find, replace, string, count) */
  $unix    = str_replace("\\", "/", $windows);

  print_r(pathinfo($unix, PATHINFO_BASENAME));

?> 

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