正则表达式匹配一条线的2个不同部分

Question

I'm working in lua, and i need to match 2 parts of a line that's taken in through file IO. I'm inexperienced with regexes and i'm told lua doesn't have full regex support built in (but i have a library that provides that if need be). Can someone help me with building regexes to match the parts necessary?

    "bor_adaptor_00.odf" 3.778
         ^^^^^^^^^^^^^^      ^^^^^
         i need this in      and this in
         a string            a number

Answer 1

I made an example:

s = '"bor_adaptor_00.odf" 3.778'
val1, val2 = string.match(s,'(%b"")%s*([.0-9]*)')
print(val1, val2)

output:

"bor_adaptor_00.odf"    3.778

Answer 2

^"(.*?)"\s+(\d[\d.]*)$

Explanation:

• ^ = line start
• "(.*?)" = save everything between " and " to a capture group
• \\s+ = any number >= 1 of whitespace chars
• (\\d[\\d.]*) = a digit followed by more digits or dots
• $ = end of line

No idea how to use that in lua, but should help to get you started.

On the other hand, this is a really simple string, so it could be a good idea to parse it without regular expressions.