如何在Perl中使用变量作为变量名？

Question

I need to achieve the following in perl

printmsg(@val1, $msg1) if @val1;
printmsg(@val2, $msg2) if @val2;
printmsg(@val3, $msg3) if @val3;
printmsg(@val4, $msg4) if @val4;
printmsg(@val5, $msg5) if @val5;
printmsg(@val6, $msg6) if @val6;

So i wrote the following snippet

for(my $i=1; $i < 6; $i++ ) {
    printmsg(@val$i, $msg$i) if @val$i;
}

It doesn't work and breaks out with errors.

Answer 1

Whenever you find yourself postfixing variable names with an integer index , realize that you should have used an array instead:

my @msgs = ('msg1', 'msg2', ..., 'msg6');
my @vals = ( [ @val1 ], [ @val2 ], ..., [ @val6 ] );

See also the FAQ How can I use a variable as a variable name?

As the answer to the FAQ notes, if the variables are not indexed by an integer, you can use a hash table:

By using symbolic references, you are just using the package's symbol-table hash (like %main:: ) instead of a user-defined hash. The solution is to use your own hash or a real reference instead.

 $USER_VARS{"fred"} = 23; my $varname = "fred"; $USER_VARS{$varname}++; # not $$varname++ 

You should read the entire FAQ list at least once a year.

Update: I purposefully left symbolic references out of my answer because they are unnecessary and likely very harmful in the context of your question. For more information, see Why it's stupid to 'use a variable as a variable name'? , part 2 and part 3 by mjd .

Answer 2

You can't just string variables together like that and get a resulting variable. You COULD evaluate the expression of $msg + i , but it's probably better if you make msg an array and just index: $msg[$i] .

Answer 3

If I understand, you need "eval"!

for(my $i=1; $i < 6; $i++ ) {
  eval 'printmsg(@val'. $i . ', $msg' . $i .') if @val' . $i;
}

But remember! All variable(@val1, @val2, ..., @valN) must exists! As you're not providing too much of your code I'm unavaiable to infer more about this problem. Maybe you could provide more code huh?