函数式转换语法如何工作？

Question

I guess I am a bit puzzled by the syntax. What does the following mean?

typedef char *PChar;
hopeItWorks = PChar( 0x00ff0000 );

Answer 1

It is equivalent to (PChar) 0x00ff0000 or (char *) 0x00ff0000 . Syntactically think of it as invoking a one-argument constructor.

Answer 2

SomeType(args) means explicit constructor call if SomeType is user-defined type and usual c-cast (SomeType)args if SomeType is fundamental type or a pointer.

PChar is equivalent to char * (pointer). Thus hopeItWorks = (char *)0x00ff0000;

Answer 3

typedef char *PChar;

Its typedef of char* to Pchar . Instead of using char* you can define variables with Pchar.

hopeItWorks = PChar( 0x00ff0000 );

Its equivalent to ==>

 hopeItWorks = (char *)( 0x00ff0000 );