如何将函数指针传递给具有可变参数的函数？

Question

I don't know how to accomplish this!
how to get the function pointer in va_list arguments?
thanks so much.

Answer 1

Typedefs often make working with function pointers easier, but are not necessary.

#include <stdarg.h>
void foo(int count, ...) {
    va_list ap;
    int i;
    va_start(ap, count);
    for (i = 0; i < count; i++) {
        void (*bar)() = va_arg(ap, void (*)());
        (*bar)();
    }
    va_end(ap);
}

Answer 2

使用typedef作为函数指针类型。