为什么复制构造函数参数为const？

Question

 Vector(const Vector& other) // Copy constructor 
 {
    x = other.x;
    y = other.y;

Why is the argument a const?

Answer 1

You've gotten answers that mention ensuring that the ctor can't change what's being copied -- and they're right, putting the const there does have that effect.

More important, however, is that a temporary object cannot bind to a non-const reference. The copy ctor must take a reference to a const object to be able to make copies of temporary objects.

Answer 2

Because you are not going to modify the argument other inside the copy ctor as it is const.

When you did x = other.x it essentially means this->x = other.x . So you are modifying only this object just by copying the values from other variable. Since the other variable is read-only here, it is passed as a const-ref.

Answer 3

The traditional copy-ctor and friends take a const& parameter for reasons specified above. However, you should also look up move-semantics and r-value references (to be part of C++0x, if all goes well) to see why and when you will use copy-ctors without a const& parameter. Another place to look at is the implementation of smart pointers such as auto_ptr (which have transfer of ownership semantics) where non-const parameters are useful.

Answer 4

为了不能改变other （偶然）？

Answer 5

当我们尝试使用copy构造函数将一个对象复制到另一个对象时，我们需要维护原始对象（我们正在复制）的原始副本，因此在传递对象时，我们使其保持不变，并将其作为按引用传递。

Answer 6

The idea of a copy constructor is that you are copying the contents of the other object into the this object. The const is there to ensure that you don't modify the other object.

Answer 7

Its not specific to copy constructor. In any function if you are not going to modify the internal state of the object then object will be passed as const .

Vector(const Vector& other) 
{
     //Since other is const, only public data member and public methods which are `const` can be accessed.
}

Answer 8

It can also come handy if you want to copy an object you only have a const reference to for example

...
const Vector& getPosition();
...

Vector* v = new Vector(getPosition());

If it wasn't for Vector(const Vector& other) that example would create a syntax error.