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使用C ++可变长度args时如何从_TCHAR *转换为char *?

[英]How do I convert from _TCHAR * to char * when using C++ variable-length args?

We need to pass a format _TCHAR * string, and a number of char * strings into a function with variable-length args: 我们需要将一个格式_TCHAR *字符串和一些char *字符串传递给一个带有可变长度args的函数:

inline void FooBar(const _TCHAR *szFmt, const char *cArgs, ...) {
  //...
}

So it can be called like so: 所以它可以这样调用:

char *foo = "foo";
char *bar = "bar";
LogToFileA(_T("Test %s %s"), foo, bar);

Obviously a simple fix would be to use _TCHAR instead of char, but we don't have that luxury unfortunately. 显然,一个简单的解决方法是使用_TCHAR而不是char,但遗憾的是我们并没有那么奢侈。

We need to use this with va_start, etc so we can format a string: 我们需要将它与va_start等一起使用,以便我们可以格式化一个字符串:

va_list args;
_TCHAR szBuf[BUFFER_MED_SIZE];

va_start(args, cArgs);
_vstprintf_s(szBuf, BUFFER_MED_SIZE, szFmt, args);
va_end(args);

Unfortunately we cannot use this because it give us this error: 不幸的是我们不能使用它,因为它给了我们这个错误:

Unhandled exception at 0x6a0d7f4f (msvcr90d.dll) in foobar.exe:
0xC0000005: Access violation reading location 0x2d86fead.

I'm thinking we need to convert our char * to _TCHAR * - but how? 我想我们需要将我们的char *转换为_TCHAR * - 但是如何?

Use %hs or %hS instead of %s. 使用%hs或%hS代替%s。 That will force the parameters to be interpretted as char* in both Ansi and Unicode versions of printf()-style functions, ie: 这将强制参数在Ansi和Unicode版本的printf() - 样式函数中被解释为char *,即:

inline void LogToFile(const _TCHAR *szFmt, ...)
{  
  va_list args;
  TCHAR szBuf[BUFFER_MED_SIZE];

  va_start(args, szFmt);
  _vstprintf_s(szBuf, BUFFER_MED_SIZE, szFmt, args);
  va_end(args);
}  

{
  char *foo = "foo"; 
  char *bar = "bar"; 
  LogToFile(_T("Test %hs %hs"), foo, bar); 
}

Usually it looks like the following: 通常它看起来如下:

char *foo = "foo";
char *bar = "bar";
#ifdef UNICODE
LogToFileW( L"Test %S %S", foo, bar); // big S
#else
LogToFileA( "Test %s %s", foo, bar);
#endif

Your question is not completely clear. 你的问题并不完全清楚。 How your function is implemented and how do you use it? 您的功能如何实现以及如何使用它?

Here was my solution - I welcome suggestions for improvement! 这是我的解决方案 - 我欢迎改进建议!

inline void FooBar(const _TCHAR *szFmt, const char *cArgs, ...) {

    va_list args;
    _TCHAR szBuf[BUFFER_MED_SIZE];

    // Count the number of arguments in the format string.
    const _TCHAR *at = _tcschr(szFmt, '%');
    int argCount = 0;
    while(at) {
        argCount++;
        at = _tcschr(at + 1, '%');
    }

    CA2W *ca2wArr[100];
    LPWSTR szArgs[100];
    va_start(args, cArgs);
    for (int i = 1; i < argCount + 1; i++) {
        CA2W *ca2w = new CA2W(cArgs);
        szArgs[i] = ca2w->m_psz;
        ca2wArr[i] = ca2w;
        cArgs = va_arg(args, const char *);
    }
    va_end(args);

    // Use the new array we just created (skips over first element).
    va_start(args, szArgs[0]);
    _vstprintf_s(szBuf, BUFFER_MED_SIZE, szFmt, args);
    va_end(args);

    // Free up memory used by CA2W objects.
    for (int i = 1; i < argCount + 1; i++) {
        delete ca2wArr[i];
    }

    // ... snip ... - code that uses szBuf
}

this is something I have used before to convert a TCHAR to char, hope it helps, although I wasn't really looking for optimization, so it's not the fastest way.. but it worked! 这是我之前用过将TCHAR转换为char的东西,希望它有所帮助,虽然我并不是真的在寻找优化,所以它不是最快的方式......但它有效!

    TCHAR tmp[255];
::GetWindowText(hwnd, tmp, 255);
std::wstring s = tmp;

//convert from wchar to char
const wchar_t* wstr = s.c_str();
size_t wlen = wcslen(wstr) + 1;
char newchar[100];
size_t convertedChars = 0;
wcstombs_s(&convertedChars, newchar, wlen, wstr, _TRUNCATE);

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