[英]How to batch execute PHP scripts from one PHP script?
I have a series of PHP scripts that I want to run in a particular order. 我有一系列要按特定顺序运行的PHP脚本。 I tried using
我尝试使用
<?php
exec('file1.php');
exec('file2.php');
exec('file3.php');
?>
to accomplish this, but just got a series of errors. 为此,但出现了一系列错误。 If I run them from the command line, they all work fine.
如果我从命令行运行它们,它们都可以正常工作。 How to fix this problem?
如何解决这个问题?
If the state of each script is well isolated (ie not clashing function/class names and global variables), you can just include each of them in turn. 如果每个脚本的状态被很好地隔离(即,不冲突函数/类名和全局变量),则可以依次包含每个脚本。
include("file1.php");
include("file2.php");
...
This will also ensure you don't spin up multiple PHP interpreters. 这还将确保您不会启动多个PHP解释器。
You can run it from the command line from your scripts, assuming you have root access. 如果您具有root用户访问权限,则可以从脚本的命令行运行它。
Example: 例:
<?php
system("php -f path/to/your/script/file1.php");
system("php -f path/to/your/script/file2.php");
system("php -f path/to/your/script/file3.php");
?>
I haven't tested it, but it should work :) 我还没有测试过,但它应该可以工作:)
system('php file1.php')
或者,仅在* nix上使用shell脚本。
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