PHP这段代码的语法有什么问题？

Question

I'm building some simple validation rules in php and my IDE (phped) is complaining about the syntax.

Can anyone tell me what is wrong with the following?

function notBlank($str) {
    (strlen($str) == 0) ? return false : return true;
}

phped complains of 'unexpected return'

Any advice appreciated.

Thanks.

Answer 1

write it like this:

function notBlank($str){
   return strlen($str) != 0;
}

Answer 2

Write it like this:

function notBlank($str) {
    return ( strlen($str) == 0 ? false : true );
}

Answer 3

You cant use return within ternary operators. If you want to keep that syntax you have to do something like this:

function notBlank($str = '') {
    $var = (strlen($str) == 0) ? false : true;
    return $var;
}

Nevertheless do notice that the default way of doing things is more legible:

function notBlank($str = '') {
    if(strlen($str) == 0)
        return false;
    else
        return true;
}

Hope it helps!

Answer 4

GSto's answer seems the best here, though you might also like to check out php's empty function:

http://www.php.net/empty

Answer 5

strlen() returns 0 when the string is empty, and in PHP 0==false . So really, it's unnecessary to wrap strlen() in a function. If you want to insist on a boolean answer then cast it. ie:

(bool) strlen($string);

So instead of your function, which is assumably called in an if block, you'd just have

if(strlen($string)) //etc.