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从控制台的Windows窗体

[英]Windows form from console

I would like to spawn a Windows form from the console using C#. 我想使用C#从控制台生成Windows窗体。 Roughly like display does in Linux, and modify its contents, etc. Is that possible? 大致类似于Linux中的display ,并修改其内容等。这可能吗?

You should be able to add a reference for System.Windows.Forms and then be good to go. 您应该能够为System.Windows.Forms添加引用,然后就可以了。 You may also have to apply the STAThreadAttribute to the entry point of your application. 您可能还必须将STAThreadAttribute应用于应用程序的入口点。

using System.Windows.Forms;

class Program
{
    [STAThread]
    static void Main(string[] args)
    {
        MessageBox.Show("hello");
    }
}

... more complex ... ... 更复杂 ...

using System.Windows.Forms;

class Program
{
    [STAThread]
    static void Main(string[] args)
    {
        var frm = new Form();
        frm.Name = "Hello";
        var lb = new Label();
        lb.Text = "Hello World!!!";
        frm.Controls.Add(lb);
        frm.ShowDialog();
    }
}

Yes, you can initialize a form in the Console. 是的,您可以在控制台中初始化表单。 Add a reference to System.Windows.Forms and use the following sample code: 添加对System.Windows.Forms的引用,并使用以下示例代码:

System.Windows.Forms.Form f = new System.Windows.Forms.Form(); 
f.ShowDialog(); 

The common answer: 常见答案:

[STAThread]
static void Main()
{    
   Application.Run(new MyForm());
}

Alternatives (taken from here ) if, for example - you want to launch a form from a thread other than that of the main application: 替代方案(取自此处 ),例如,您想要从主应用程序以外的线程启动表单:

Thread t = new Thread(new ThreadStart(StartNewStaThread)); 

// Make sure to set the apartment state BEFORE starting the thread. 
t.ApartmentState = ApartmentState.STA; 
t.Start(); 

private void StartNewStaThread() { 
    Application.Run(new Form1()); 
} 

.

Thread t = new Thread(new ThreadStart(StartNewStaThread)); 
t.Start();

[STAThread]
private void StartNewStaThread() { 
    Application.Run(new Form1()); 
} 

You can try this 你可以试试这个

using System.Windows.Forms;

[STAThread]
static void Main() 
{
    Application.EnableVisualStyles();
    Application.Run(new MyForm()); 
}

Bye. 再见。

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