[英]jQuery select items which parents are not of a given class
how can select all nodes with class "myClass" whose parent nodes don't have class "myClass". 如何选择父节点没有类“ myClass”的所有类“ myClass”的节点。
for example, i have following HTML: 例如,我有以下HTML:
<div class="myContainer">
<div class="myClass" id="d1">
<div class="myClass" id="d2"></div>
<div class="myClass" id="d4"></div>
</div>
<div class="myClass" id="d3"></div>
</div>
and i want to get a list of elements with ids "d1" and "d3" 而且我想获得ID为“ d1”和“ d3”的元素列表
actually, i'm trying to write a code that converts HTML from that example to a list with tabulations, such as: 实际上,我正在尝试编写代码,将示例中的HTML转换为带有列表的列表,例如:
d1
d2
d4
d3
(there can be more descedant nodes) (可以有更多的后继节点)
I have come up with a number of possible solutions. 我提出了许多可能的解决方案。 Maybe:
也许:
$(":not(.myClass) > .myClass")
Or if you want to look beyond the direct parent: 或者,如果您想超越直接父项:
$(":not(.myClass) .myClass")
This might work also: 这也可能起作用:
$(".myClass:has(:not(.myClass))")
A better solution for your exact example: 为您的确切示例提供更好的解决方案:
$(".myContainer > .myClass")
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