将双精度格式转换为货币格式以C＃输出字符串的最快/最佳方法是什么？

Question

When using .ToString("{blah}") it gives an error because it's a ?double not a double... 'bad parameter' etc

Note this does not seem to be working, sometimes I get '5.7':

double itemListPrice = Math.Round((double)((item.UserIntervalPrice * item.Volume) - 
    ((item.UserIntervalPrice * item.Volume) * (item.VolumeDiscount / 100))),2);

htmlReceipt += "<tr><td>" + item.Title + "</td><td>" + item.Description + "</td><td>" + 
    item.Volume + "</td><td>$" + itemListPrice.ToString() + "</td></tr>";

Answer 1

Have you tried:

double? myDouble = 10.5;

if (myDouble.HasValue)
{
    string currency = myDouble.Value.ToString("c");
}

Answer 2

I find the following to work quite well:

double? val1 = null;
double? val2 = 5.7d;

var s1 = string.Format("{0:c}", val1);  // outputs: ""
var s2 = string.Format("{0:c}", val2);  // outputs: $5.70

I wouldn't worry too much about performance in this case, and be more concerned with correctness and clarity, myself.

I would also suggest you consider using string.Format() or a StringBuilder in lieu of concatenating string fragments individually. Not this this is a huge deal, but it does allocate and discard intermediate strings unnecessarily; which, if you're concerned about performance you'd probably want to eliminate; for example:

htmlReceipt += 
   string.Format( "<tr><td>{0}</td><td>{1}</td><td>{2}</td><td>{3:c}</td></tr>",
                   item.Title, item.Description, item.Volume, item.listPrice );

Answer 3

使用小数来处理货币值，并使用Decimal.ToString（“ C”）进行格式化。

Answer 4

好吧，看起来像这样工作：

((double)theVariable).ToString("c");