[英]Fatal error: Using $this when not in object context
here is the part if having error. 如果有错误,这是部分。
Fatal error: Using $this when not in object context in /pb_events.php on line 6
致命错误:在第6行的/pb_events.php中不在对象上下文中时使用$ this
line 6 is: $jpp = $this->vars->data["jpp"];
第6行是:
$jpp = $this->vars->data["jpp"];
function DoEvents($this) {
global $_CONF, $_PAGE, $_TSM , $base;
$jpp = $this->vars->data["jpp"];
$cache["departments"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_departments]}");
$cache["locations"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_location]}");
$cache["names"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_names]}");
$cache["categories"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_categories]}");
Thanks a lot! 非常感谢! appreciate!
欣赏!
$this only makes sense in methods, not in functions $这只在方法中有意义,而不是在函数中
this is ok 还行吧
class Foo {
function bar() {
$this->...
this is not 这不是
function some() {
$this->
// edit: didn't notice he passes "$this" as parameter //编辑:没有注意到他将“$ this”作为参数传递
advice: simply replace "$this" with "$somethingElse" 建议:简单地用“$ somethingElse”替换“$ this”
You cannot pass $this
to a procedural function. 你不能将
$this
传递给程序函数。 $this
is a reserved variable. $this
是一个保留变量。
As per my comments. 根据我的评论。 You want to use
$this
as passed variable and php doesn't allow it outside class methods body. 你想使用
$this
作为传递变量而php不允许它在类方法体外。
function DoEvents($obj) {
global $_CONF, $_PAGE, $_TSM , $base;
$jpp = $obj->vars->data["jpp"];
$cache["departments"] = $obj->db->QFetchRowArray("SELECT * FROM {$obj->tables[job_departments]}");
$cache["locations"] = $obj->db->QFetchRowArray("SELECT * FROM {$obj->tables[job_location]}");
$cache["names"] = $obj->db->QFetchRowArray("SELECT * FROM {$obj->tables[job_names]}");
$cache["categories"] = $obj->db->QFetchRowArray("SELECT * FROM {$obj->tables[job_categories]}");
You have to make the object first. 你必须先把对象做好。
$object=new Myobject;
DoEvents($object);
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