％C在GCC内联汇编代码中的含义是什么？

Question

I am trying to understand this inline assembly code which comes from _hypercall0 here .

asm volatile ("call hypercall_page+%c[offset]" \
        : "=r" (__res) \
        : [offset] "i" (__HYPERVISOR_##name * sizeof(hypercall_page[0])) \
        : "memory", "edi", "esi", "edx", "ecx", "ebx", "eax") 

I am having trouble finding information on what %c in the first line means. I did not find any information in the most obvious section of the GCC manual , which explains %[name] , but not %c[name] . Is there any other place I should look at?

Answer 1

From the GCC internals documentation :

`%c digit ' can be used to substitute an operand that is a constant value without the syntax that normally indicates an immediate operand.

Answer 2

Check the assembly output (with gcc -S , or maybe disassemble the object file) and it may be clearer.

My guess is that it stands for . hypercall_page looks like a table of instructions that each do a syscall. Maybe this will generate a call hypercall_page + {constant based on the expression given} , essentially having computed the address of this offset at compile time.

As an aside, this __HYPERVISOR##name stuff really reminds me of the __NR_name_of_syscall type convention you see for syscalls in Linux's <asm/unistd.h> and similar places.