C ++中的Bitflag枚举

Question

Using enums for storing bitflags in C++ is a bit troublesome, since once the enum values are ORed they loose their enum-type, which causes errors without explicit casting.

The accepted answer for this question suggests overloading the | operator:

FlagsSet operator|(FlagsSet a, FlagsSet b) 
{ 
    return FlagsSet(int(a) | int(b)); 
}

I'd like to know if this method has any runtime implications?

Answer 1

Runtime implications in terms of correctness? No - this should be exactly what you want.

Runtime implications in terms of speed? I would expect any decent compiler to optimize this away properly to the minimal number of instructions for a release build (although you might want to add inline just to be sure).

Answer 2

It potentially does three copies and a function call, barring RVO, registers, and/or inlining optimizations.

Naked bitwise OR operations themselves usually decompose to a single processor instruction.

Answer 3

The code is correct.

The code will be the same speed as without type casts.

But whether the code is fast is irrelevant, because a type named 'FlagSet' will most probably be used in a context of conditionals test (-> "if (Flag)"), which is more of a hit to speed than a bit wise 'or' of two values of the size of a register.

Answer 4

使用std :: bitset作为您的位标志...更简单;）或boost :: dynamic_bitset。