[英]How to find all coupling bracket with regular expression?
I'd like to have one regular expression to find all curly brackets and replace them with other strings. 我想要一个正则表达式来查找所有大括号并将其替换为其他字符串。
For example, I want to replace " {foo} " with " FOO " and " {bar} " with " BAR " and " {} " with " EMPTY ". 例如,我想用“ FOO ”替换“ {foo} ”,用“ BAR ”替换“ { bar} ”,用“ EMPTY ”替换“ {} ”。 If the input is " abc {foo} def {bar} {} ", then the output is " abc FOO def BAR EMPTY ".
如果输入为“ abc {foo} def {bar} {} ”,则输出为“ abc FOO def BAR EMPTY ”。
Nested brackets or un-coupled brackets are not allowed. 不允许使用嵌套括号或非耦合括号。 If character "{" or "}" is necessary.
如果需要字符“ {”或“}”。 It should be doubled.
应该加倍。 So, "{{ def }}" is just "{ def }".
因此,“ {{def}}”仅仅是“ {def}”。
Other string in {} is not allowed. 不允许在{}中使用其他字符串。 Say, I just want " {foo} " and " {bar} ".
说,我只想要“ {foo} ”和“ {bar} ”。 So, " abc {xyz} def " should be recognized as invalid input.
因此,应将“ abc {xyz} def ”识别为无效输入。
If you have negative lookbehinds/lookaheads available: 如果您有否定的后顾之忧/前瞻功能:
(?<!{){([a-z]+)}(?!})
and replace with the value of the matching group. 并替换为匹配组的值。
The ([az]+)
matches your contained character string, the (?<!{)
makes sure there isn't a second {
before your {
, and the (?!})
makes sure there isn't a second }
after your }
. ([az]+)
匹配您包含的字符串, (?<!{)
确保在{
之前没有第二个{
,而(?!})
确保在之后没有第二个}
您的}
。
If you don't have lookbehinds/lookaheads, then 如果您没有后顾之忧,那么
(?^|[^{]){([a-z]+)}(?$|[^})
I would first go and replace {}
with EMPTY
without using a regular expression. 我首先要使用
EMPTY
替换{}
而不使用正则表达式。
Then use 然后使用
(?<!{){(foo|bar)}(?!})
to match {foo}
or {bar}
but not {}
or {{anything}}
or {anything}
匹配
{foo}
或{bar}
但不匹配{foo}
{}
或{{anything}}
或{anything}
Backreference no. 反向编号 1 contains the matched text.
1包含匹配的文本。
So a code snippet could look like 因此,代码段可能看起来像
Regex matches = new Regex(@"(?<!\{)\{(foo|bar)\}(?!\})", RegexOptions.IgnoreCase);
resultString = matches.Replace(subjectString, "$1".ToUpper());
(I hope that calling ToUpper() on a string works; I don't know C#, so please correct me if I'm wrong) (我希望在字符串上调用ToUpper()可以工作;我不知道C#,所以如果我错了,请纠正我)
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