PHP continue 语句

Question

When reading a PHP book I wanted to try my own (continue) example. I made the following code but it doesn't work although everything seems to be ok

$num2 = 1;

    while ($num2 < 19)
        {
            if ($num2 == 15) { 
            continue; 
            } else {
            echo "Continue at 15 (".$num2.").<br />";
            $num2++;
            }

        }

The output is

Continue at 15 (1).
Continue at 15 (2).
Continue at 15 (3).
Continue at 15 (4).
Continue at 15 (5).
Continue at 15 (6).
Continue at 15 (7).
Continue at 15 (8).
Continue at 15 (9).
Continue at 15 (10).
Continue at 15 (11).
Continue at 15 (12).
Continue at 15 (13).
Continue at 15 (14).

Fatal error: Maximum execution time of 30 seconds exceeded in /var/www/php/continueandbreak.php on line 20

Line 20 is that line

if ($num2 == 15) { 

Would you please tell me what's wrong with my example ? I am sorry for such a Noob question

Answer 1

if you don't increment $num2 before the continue you will get into an infinite loop;

$num2 = 0;

while ($num2 < 18)
    {
            $num2++;
            if ($num2 == 15) { 
              continue; 
            } else {
              echo "Continue at 15 (".$num2.").<br />";
            }


    }

Answer 2

You don't even need continue there, your code equivalent to;

$num2 = 1;
while ($num2 < 19){
    if ($num2 != 15) { 
        echo "Continue at 15 (".$num2.").<br />";
        $num2++;
    }
}

If that's not what you're trying to achieve, you're using continue wrong.

Answer 3

in php, use foreach for arrays and for for looping

for($num = 1; $num < 19; $num++) {
    if ($num != 15) { 
       echo "Continue at 15 (" . $num . ") . <br />";
       break;
    }   
}