[英]PHP regex not new line
How do I have a regex statement that accepts any character except new lines. 如何使用接受除新行之外的任何字符的正则表达式语句。 This includes anything but also includes new lines which is not what i want:
这包括任何东西,但也包括新的行,这不是我想要的:
"/(.*)/"
The dot .
点
.
does not match newlines unless you use the s
modifier. 除非使用
s
修饰符,否则与换行符不匹配。
>>> preg_match("/./", "\n")
0
>>> preg_match("/./s", "\n")
1
以下正则表达式应匹配除换行符之外的任何字符
/[^\n]+/
The default behavior shouldn't match a new line. 默认行为不应与新行匹配。 Because the "s" modifier is used to make the dot match all characters, including new lines.
因为“s”修饰符用于使点匹配所有字符,包括新行。 Maybe you can provide an example to look at?
也许你可以提供一个例子来看看?
#!/usr/bin/env php
<?php
$test = "Some\ntest\nstring";
// Echos just "Some"
preg_match('/(.*)/', $test, $m);
echo "First test: ".$m[0]."\n";
// Echos the whole string.
preg_match('/(.*)/s', $test, $m);
echo "Second test: ".$m[0]."\n";
So I don't know what is wrong with your program, but it's not the regex (unless you have the /s
modifier in your actual application. 所以我不知道你的程序有什么问题,但它不是正则表达式(除非你的实际应用程序中有
/s
修饰符。
this is strange, because by default the dot (.) does not accept newlines. 这很奇怪,因为默认情况下,点(。)不接受换行符。 Most probably you have a "\\r" (carriage return) character there, so you need to eliminate both:
/[^\\r\\n]/
很可能你有一个“\\ r”(回车)字符,所以你需要消除两者:
/[^\\r\\n]/
ah, you were using /s 啊,你用的是/ s
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