等效于C＃中的PHP fmod

Question

Does anybody know what the C# equivalent of fmod is? I'm trying to convert this line of code to C#.

$lon_rad = fmod(($long1+$dlon_rad + M_PI), 2*M_PI) - M_PI;

Here's what I have so far. I just need the fmod converted.

double lon_rad = ((lon1+dlon_rad + Math.PI), 2*Math.PI) - Math.PI;

Answer 1

其他人给了正确的运算符，但没有给出完整的语法，这是：

double lon_rad = ((lon1+dlon_rad + Math.PI) % (2*Math.PI)) - Math.PI;

Answer 2

Use a P/Invoked call into the standard library (from here ):

[DllImport("msvcrt.dll")]
static extern double fmod(double x, double y);

Answer 3

您是否尝试过％模数运算符？

Answer 4

public static double fmod(double dividend, double divisor )
{
    double Modulus = 
                     (Math.Abs(dividend) - (Math.Abs(divisor) * 
                     (Math.Floor(Math.Abs(dividend) / Math.Abs(divisor))))) * 
                     Math.Sign(dividend);

    return Modulus;
}