如何在iPhone应用程序中使用位类型？

Question

I'm writing an iPhone app that's a mixture of Objective-C and C. I have 32-bit integer flags throughout my code that take on only two distinct values: 0 and 1. I'd like to use a data type that's smaller than 32 bits.

Is there a type that's only one bit? What is the size of "BOOL" in Objective-C?

One solution I've considered is using one 32-bit integer for a group of 32 flags... then checking each flag in the following way:

if(ALL_FLAGS & (1 << SPECIFIC_FLAG)){...}

I'd really like to use just a "bit" type though.

Cheers!

Answer 1

The BOOL type under Objective C (actually it's a Cocoa definition, OBJC itself doesn't know the BOOL type) is using one byte. This is different from the Windows 32 BOOL which is equivalent to int or 32 bit.

With smaller types you can use the typical C/C++ methods, either with bit shifts like in your example above or bit structures (in which case the compiler will do the bit shifting and testing).

typedef struct {
    unsigned someflag:1;
    unsigned anotherflag:1;
    unsigned yetnoather:1;
} MYFLAGS ;


MYFLAGS allflags;  

allflags.anotherflag= TRUE; 

if (allflags.anotherflag) { /* somecode */ }

Answer 2

还有一个CFBitVector，您可以在其中保存一组值...

Answer 3

Here are the definitions for the BOOL type, you could define your own type in the same way:

typedef signed char     BOOL; 
// BOOL is explicitly signed so @encode(BOOL) == "c" rather than "C" 
// even if -funsigned-char is used.
#define OBJC_BOOL_DEFINED


#define YES             (BOOL)1
#define NO              (BOOL)0