Array.each输出所有方法

Question

Why would...

for(var k in this.errors) {
        $('error_list').insert({
            bottom: new Element('li').update(k + ' :'+this.errors[k])
        })
    }

...output put all Prototype enumerable methods, plus what I've added to the array?

I'm building an associative array:

this.errors['email'] = 'Your email is invalid';

Answer 1

您需要使用“ hasOwnProperty”来防止这种情况。

Answer 2

You may prevent this using hasOwnProperty :

for(var k in this.errors) {
    if (this.errors.hasOwnProperty(k)) {
        $('error_list').insert({
            bottom: new Element('li').update(k + ' :'+this.errors[k])
        })
    }
}

Answer 3

Try this:

$H(this.errors).each(function(error) {
    $('error_list').insert({
        bottom: new Element('li').update(error.key + ': ' + error.value)
    })
})