在Django中获取唯一的外键？

Question

Suppose my model looks like this:

class Farm(models.Model):
   name = ...

class Tree(models.Model):
   farm = models.ForeignKey(Farm)

...and I get a QuerySet of Tree objects. How do I determine what farms are represented in that QuerySet ?

Answer 1

http://docs.djangoproject.com/en/dev/ref/models/querysets/#in

Farm.objects.filter(tree__in=TreeQuerySet)

Answer 2

使用Django ORM可能有更好的方法来保持懒惰，但你可以通过常规python得到你想要的东西（在我的头顶）：

>>> set([ t.farm for t in qs ])

Answer 3

Here is a way to have the database do the work for you:

farms = qs.values_list('farm', flat=True).distinct() 
#values_list() is new in Django 1.0

return value should evaluate to something like:

(<Farm instance 1>, <Farm instance5>)

were farms will be those that have trees in that particular query set.

For all farms that have trees, use qs = Tree.objects

Keep in mind that if you add order_by('some_other_column') then distinct will apply to the distinct combinations of 'farm' and 'some_other_column', because other column will also be in the sql query for ordering. I think it's a limitation (not an intended feature) in the api, it's described in the documentation .