在C中逐行读取文件

Question

I am trying to write some code that will open a file, read its content line by line and store each of these lines into an array.

First I open the file and count the number of lines, each of the lines is of a fixed length so I simply do this :

    char buf2[LINE_LENGTH];
    int in2 = open("toSend2", O_RDONLY);
    int number_of_lines = 0;

    for (;;)
 {
  char* p2 = buf2;
  int count = read (in2, p2, LINE_LENGTH);
  if (count < 0)
  {
    printf("ERROR");
    break;
  }
  if (count == 0) break; 

  number_of_lines++;

  printf("count: %d \n",count);
  printf("File 2 line : %s", p2);
  printf("\n");

 }
 close (in2);

So far, this works well, number_of_lines is indeed the number of lines in the file "toSend2" and each of my printf are the lines contained in that file.

Now with the number of lines, I create an array of strings and then I basically go through the whole file again but this time, I would like to store each of the lines in the array (there's probably a better way to find out the number of lines in a file, but everything that I tried has failed !)

    char * array[number_of_lines];
    int b=0;
    int in3=0;
    in3 = open("toSend2", O_RDONLY);
    for (;;)
 {
  char* p3 = buf3;
  int count = read (in2, p3, LINE_LENGTH);
  if (count < 0)
  {
    printf("ERRORRRRRR");
    break;
  }
  if (count == 0) break;


  array[b] = p3;
  b++;

  printf("count: %d \n",count);
  printf("FILE 2 LINEEEEEE : %s", p3);
  printf("\n");

 }  
 close(in3);

This, of course, doesn't work : each of my printf are the right line plus the last line of the file, for example, the first printf would be :

FILE 2 LINEEEEEEE : "1st line of the file" "last line of the file"

And after this for loop, when I trace the contents of my array, every item in it is simply the last line of the file. I think this is because I simply put the same pointer (pointing to a different line at that moment) in the array each time, but in the end it will point to the last line, therefore everything will be the last line.

How would I solve my problem ?

ps: I just started C, so please do not assume I know even basic things about it :(

Answer 1

• Use stdio, ie fopen() , fgets() and fclose() to do the I/O. You're using much lower-level Posix-style I/O, for no good reason.
• You will need to dynamically allocate each new line in order to store it in the array. You can use strdup() to do this.
• Remember that things can go wrong; files can fail to open, lines can fail to read in, and memory can fail to be allocated. Check for this, and act accordingly.

Answer 2

You haven't created an array of strings, you've created a pointer to an array of strings. you need to malloc your array in part2 to be count of lines * number of char's per line. then move your read lines into each subsequent position of array.

[edit]
one more thing.....
your strings are X length. 'C' strings aren't X length, they're X+1 length :)
[/edit]

Answer 3

为什么不使用fopen，然后仅使用fgets获取每一行

Answer 4

You can use stat to get the file size. Then number_of_lines = stat.st_size/LINE_LENGTH

If you don't need your character strings nul-terminated, you can read the whole file into a single buffer. Set up the array of pointers if you really want them, or just use &buf[n * LINE_LENGTH] to get the start of line n .

To print a non-nul terminated string of known length, you can use:

printf("line %d = '%.*s'\n", n, LINE_LENGTH, &buf[n * LINE_LENGTH]);

Let me know in a comment if you want to see actual code.