在jQuery选择器中使用jQuery对象

Question

I'm fairly new to jQuery, and think I might be making something harder than it needs to be. I've got a jQuery variable that is just an unordered list. It was declared this way:

var $list = $('#activityList'); // activityList is ID of <ul>

I'm trying to select all <li> elements within that list using the variable I've created:

$items = $('#' + $list.attr('id') + ' > li');

Does anyone know if there's a different syntax to achieve the same thing without having to break the variable down to it's id attribute?

Thanks.

Clarification: I used simplified code for the purposes of asking the question, but I do want to make use of the jQuery variable "$list" within the selector, rather than hardcoding the ID.

Answer 1

$items = $('li', $list); 

那应该做你想要的。

Answer 2

$("#activitylist > li") would work, as > traverses content. You can also use, with $list as a JQuery object:

$list.find("li") or $list.children("li") to find the list items as well. children would be more efficient if you are only looking for immediate children.

Answer 3

尝试这个：

var items = $('#activityList > li');

Answer 4

也许我误解了，但是错在哪里......

var $items = $('#activityList > li');