C中的语法错误

Question

I am trying to build a block where I am getting this error message

pprbc_CONTENT_icverification_act.c", line 99.2: 1506-018 (S) Operand of indirection operator must be a pointer expression

Can anyone please explain what this means?

code below:

   *(WORK_migration_ind_f) =
   *(migration_status_in_MI9_CIRCLE_INFO(WORK_source_circle_f));

Answer 1

Yes, you put a '*' in front of something that isn't a pointer.

You'd be doing yourself and everybody a favor if you posted the line of code involved.

Answer 2

Presumably you have code something like this:

int x;

*x;    // apply indirection to non-poiner

But it's impossible to say without seeing the actual code that causes the error message.

Answer 3

The * (indirection) operator dereferences a pointer; that is, it converts a pointer value to an l-value. The operand of the indirection operator must be a pointer to a type.

Answer 4

Either the variable WORK_migration_ind_f or the return type of the function migration_status_in_MI9_CIRCLE_INFO (or both) is not a pointer type. You can dereference only a pointer.

If you have code like:

int *pi;
int i;
int f(void);
int *pf(void);

Then, the following "makes sense":

*pi /* is of type int */
*pf() /* is of type int */

The following doesn't:

*i /* can't dereference a non-pointer */
*f() /* can't dereference a non-pointer */

If you show us the declarations of WORK_migration_ind_f and WORK_migration_ind_f , we can tell you more, but I think you should be able to figure the error out on your own now.