C ++中用于String.format（）的Java中％ld的等效项

Question

For instance, %11.2lf in C++ becomes %11.2f in Java. How about for long format?

Answer 1

As you may have worked out, it's not necessary to specify the l flag. According to the docs , a decimal integer is specified by d just like in C++. So the answer is just %d .

Answer 2

Use %d for decimals (long, int). It works OK. Eg:

System.err.println(String.format("%d", 193874120937489387L));

...will print just fine. Read up on java.util.Formatter for more details. %d will take a long , no problem.