Ruby class_eval和yield

Question

Man, I'm peeling the layers of the onion today, anyway here's the code

class MyClass
  def initialize(dynamic_methods)
    @arr = Array.new(dynamic_methods)
    @arr.each { |m|
      self.class.class_eval do
        define_method(m) do
          "<#{yield self if block_given?}>" 
        end
      end
    }
    end
end

tmp = MyClass.new ['method1', 'method2', 'method3']
tmp.method1 do |t|
  "here"
end

My problem is that I'm trying to access "here" within define_method(m) when the method is being executed, not when created. The current statement "<#{yield self if block_given?}>" doesn't give me that. And in case you are wondering, I have to keep this part of the code as is but I can make all the changes I want to MyClass.

tmp = MyClass.new ['method1', 'method2', 'method3']
tmp.method1 do |t|
  "here"
end

Can anyone help with the syntax? Thanks in advance for your help.

UPDATE: See below for my answer.

Answer 1

Try replacing

define_method(m) do
  "<#{yield self if block_given?}>" 
end

with:

define_method(m) do |&block|
  "<#{block.call if block}>" 
end

This should work for 1.8.7 and up. You may also try to use module_eval :

self.class.module_eval %Q{
  def #{m}(&block)
    "<\#{block.call if block}>"
  end
}

Answer 2

With a lot of feedback from Sergei and some tinkering on my own, I manage to get it working

class MyClass
  def initialize(dynamic_methods)
    @arr = Array.new(dynamic_methods)
    @arr.each { |m|
      self.class.module_eval %Q{
        def #{m}(&block)
          yield(self) if block_given?
        end
      end
    }
    end
end

tmp = MyClass.new ['method1', 'method2', 'method3']
tmp.method1 do |t|
  "here"
end

As you can tell, there are some minor tweaks to Sergei's suggestions, so thanks for all your help Sergei.