C ++错误C2059

Question

Solved

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When I try to compile this program i keep getting these errors:

(50) : error C2059: syntax error : '<='

(50) : error C2143: syntax error : missing ';' before '{'

(51) : error C2059: syntax error : '>'

(51) : error C2143: syntax error : missing ';' before '{'

(62) : error C2059: syntax error : 'else'

(62) : error C2143: syntax error : missing ';' before '{'

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#include <iostream>
#include <string>
#include <cassert>
using namespace std;

class income {
private:
    double incm;
    double subtract;
    double taxRate;
    double add;
    char status;
public:
    void setStatus ( char stats ) { status = stats; }
    void setIncm (double in ) { incm = in; }
    void setSubtract ( double sub ) { subtract = sub; }
    void setTaxRate ( double rate ) { taxRate = rate; }
    void setAdd ( double Add ) { add = Add; }

    char getStatus () { return status; }
    double getIncm () { return incm; }
    double getsubtract () { return subtract; }
    double getTaxRate () { return taxRate; }
    double getAdd () { return add; }
    void calcIncome ();
};

//calcIncome
int main () {
    income _new;
    double ajIncome = 0, _incm = 0;
    char status = ' ';
    bool done = false;
    while ( !done ) {
        cout << "Please enter your TAXABLE INCOME:\n" << endl;
        cin >> _incm;
        if(cin.fail()) { cin.clear(); }
        if ( _incm <= 0) { cout << "the income must be greater than 0... \n" << endl; }
        if ( _incm > 0) { done = true; _new.setIncm(_incm); }
    }

    done = false;
    char stt [2] = " ";
    while ( !done ) {
        cout << "Please declare weather you are filing taxes jointly or single" << "\n";
        cout << "\t's' = single\n\t'm' = married" << endl;
        cin >> stt;
        if(cin.fail()) { cin.clear(); }
        if ( status == 's' || status == 'm' ) { done = true; _new.setStatus(stt[0]); }
        //if else { }
    }

    return 0;
};

This is part of a homework assignment so any pointers on bettering my programing would be **great**

Note:I am using Windows 7 with VS express C++ 2008

Answer 1

Your variable is named incom , not income . income refers to a type, so the compiler gets confused and you get a syntax error when you try to compare that type against a value in line 50.

One note for bettering you programming would be to use more distinct variable names to avoid such confusions... ;)

Answer 2

income is the name of your class. _incm is the name of your variable. Perhaps you meant this (notice the use of _incm not income ):

if (_incm <= 0) { cout << "the income must be greater than 0... \n" << endl; }
if (_incm > 0) { done = true; _new.setIncm(_incm); }

Frequently you use CamelCase for class names and lowercase for instance variable names. Since C++ is case-sensitive, they wouldn't conflict each other if they use different case.