为什么不能例如List <ChildClass> 传递给一个接受List的方法 <ParentClass> 作为参数？

Question

Simple example:

public class Person
{
    String name;
}

public class VIP extends Person
{
    String title;
}

And then doing:

public static void main(String[] args)
{
    Person p = new Person();
    p.name = "John";

    VIP vip = new VIP();
    vip.name = "Bob";
    vip.title = "CEO";

    List<Person> personList = new ArrayList<Person>();
    List<VIP> vipList = new ArrayList<VIP>();

    personList.add(p);
    personList.add(vip);

    vipList.add(vip);

    printNames(personList);
    printNames(vipList);
}

public static void printNames(List<Person> persons)
{
    for (Person p : persons)
        System.out.println(p.name);
}

gives an error on "printNames(vipList)" (required List<Person> found List<VIP>).

Does this mean that although VIP is a Person, List<VIP> is not a List<Person>?

Answer 1

That's right. A list of bananas is not a list of fruit. Otherwise you could insert any fruit in a list of bananas. eg

List<Fruit> lf = new List<Banana>();
lf.add(new Apple());

would result in unexpected or counterintuitive results.

Answer 2

You're just prohibited by the rules of Generics . If you're rather interested in how to "fix" this behaviour, just change the printNames() method to take a List<? extends Person> List<? extends Person> argument instead.

Answer 3

Bjarne Stroustrup, inventor of C++, explains it rather well:

http://www2.research.att.com/~bs/bs_faq2.html#conversion

Yes, I know I am late for this party, but better than never, right..