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WPF重点项目

[英]WPF Highlight Item

I have a ViewModel that provides a collection of Items. 我有一个ViewModel提供项目的集合。 There is also a ActiveItem propery. 还有一个ActiveItem属性。 The Items collection may or may not contain ActiveItem. Items集合可能包含或可能不包含ActiveItem。

What I want to do (in XAML) is display the items as a list and highlight any of the items that are equal to Active Item. 我想做的(在XAML中)是将项目显示为列表,并突出显示与“活动项目”相同的任何项目。

I have tried the following with no success: 我尝试了以下方法,但均未成功:

<ListBox ItemsSource="{Binding Items}">
    <ListBox.ItemTemplate>
        <DataTemplate>
            <Border x:Name="outerBorder" Background="Green">
                <TextBlock Text="{Binding ItemId}" />
            </Border>
            <DataTemplate.Triggers>
                <DataTrigger 
                    Binding="{Binding      
                        Path=DataContext.Item.ItemId,      
                        RelativeSource={RelativeSource TemplatedParent},     
                        Mode=Default}"
                    Value="{Binding      
                        Path=DataContext.ActiveItem.ItemId,      
                        RelativeSource={RelativeSource AncestorType=Window},     
                        Mode=Default}"
                >
                    <Setter TargetName="outerBorder" 
                        Property="Background" Value="Orange" />
                </DataTrigger>
            </DataTemplate.Triggers>
        </DataTemplate>
    </ListBox.ItemTemplate>
</ListBox>

As you can see I attempted to use a DataTrigger to match the current item with the ActiveItem but it doesn't work. 如您所见,我尝试使用DataTrigger将当前项与ActiveItem匹配,但是它不起作用。 I think this is something to do with my trying to use a Binding in DataTrigger.Value - something I haven't seen any other examples of. 我认为这与我尝试在DataTrigger.Value中使用Binding有关-我没有见过其他示例。

Any ideas how I might make this work? 有什么想法可以使我工作吗?

Thanks, 谢谢,

Daniel 丹尼尔

Since you're using MVVM, why not just have the view model expose a property telling the view whether it's active or not? 由于您使用的是MVVM,为什么不只让视图模型公开一个告诉视图是否处于活动状态的属性? That'll get that logic out of you view and into your VM. 这样一来,逻辑就可以从您的视图进入VM。

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