将小数格式化为两个位置或整数

Question

For 10 I want 10 and not 10.00 For 10.11 I want 10.11

Is this possible without code? ie by specifying a format string alone simlar to {0:N2}

Answer 1

decimal num = 10.11M;

Console.WriteLine( num.ToString( "0.##" ) );

Answer 2

It seems to me that the decimal precision is intrinsic to the decimal type, which defaults to 4 decimal places. If I use the following code:

decimal value = 8.3475M;
Console.WriteLine(value);
decimal newValue = decimal.Round(value, 2);
Console.WriteLine(newValue);

The output is:

8.3475
8.35

Answer 3

This can be achieved using CultureInfo. Use the below using statement to import the library.

using System.Globalization;

For the decimal conversion, ## can be used for optional decimal places and 00 can be used for mandetory decimal places. Check the below examples

double d1 = 12.12;
Console.WriteLine("Double :" + d1.ToString("#,##0.##", new CultureInfo("en-US")));

String str= "12.09";
Console.WriteLine("String :" + Convert.ToDouble(str).ToString("#,##0.00", new CultureInfo("en-US")));

String str2 = "12.10";
Console.WriteLine("String2 with ## :" + Convert.ToDouble(str2).ToString("#,##0.##", new CultureInfo("en-US")));
Console.WriteLine("String2 with 00 :" + Convert.ToDouble(str2).ToString("#,##0.00", new CultureInfo("en-US")));


int integ = 2;
Console.WriteLine("Integer :" + Convert.ToDouble(integ).ToString("#,##0.00", new CultureInfo("en-US")));

the results are as follows

Double :12.12
String :12.09
String2 with ## :12.1
String2 with 00 :12.10
Integer :2.00