如何为 TableView 创建 NSIndexPath

Question

I need delete row 1 of a table in a function I have defined. In order to use deleteRowAtIndexPath you must use an IndexPath with a section and row defined. How can I create an indexpath like this?

An array with the int {1} as its only member will crash; the NSLog message states that the section needs to be defined as well.

*Edit -> Code relating to cell delete:

    NSIndexPath *myIP = [[NSIndexPath alloc] indexPathForRow:0 inSection:0];
    NSArray *myArray = [[NSArray alloc] initWithObjects:myIP, nil];
//  [self.tableView beginUpdates];
    [self.tableView deleteRowsAtIndexPaths:myArray withRowAnimation:UITableViewRowAnimationFade];
//  [self.tableView endUpdates];

Answer 1

Use [NSIndexPath indexPathForRow:inSection:] to quickly create an index path.

Edit: In Swift 3:

let indexPath = IndexPath(row: rowIndex, section: sectionIndex)

Swift 5

IndexPath(row: 0, section: 0)

Answer 2

indexPathForRow is a class method!

The code should read:

NSIndexPath *myIP = [NSIndexPath indexPathForRow:0 inSection:0] ;

Answer 3

Obligatory answer in Swift : NSIndexPath(forRow:row, inSection: section)

You will notice that NSIndexPath.indexPathForRow(row, inSection: section) is not available in swift and you must use the first method to construct the indexPath.

Answer 4

对于 Swift 3，它现在是： IndexPath(row: rowIndex, section: sectionIndex)