[英]Why Does Test Condition of “for(;;)” Succeed?
Insomuch as I understand "for(;;)" has no initial condition, no test condition and no increment condition, and therefore loops forever, I am curious why the test condition succeeds each loop. 因为我理解“for(;;)”没有初始条件,没有测试条件和没有增量条件,因此永远循环,我很好奇为什么测试条件成功每个循环。
Does the empty expression ";" 空表达式是否为“;” evaluate as true in C?
在C中评估为真? Or is this a special case handled by compilers?
或者这是由编译器处理的特殊情况?
This is by the definition of the for
statement in the C language. 这是通过C语言中
for
语句的定义。 6.8.5.3/2 "The for
statement": 6.8.5.3/2“的
for
声明”:
Both clause-1 and expression-3 can be omitted.
可以省略子句-1和表达式3。 An omitted expression-2 is replaced by a nonzero constant .
省略的表达式-2由非零常量替换 。
C language has no such thing as "empty expression". C语言没有“空表达”这样的东西。 If any expression is missing from the
for
statement, syntactically it means that the entire expression is omitted , not that it is there, but empty. 如果
for
语句中缺少任何表达式,从语法上讲,它意味着整个表达式被省略 ,而不是它在那里,而是空的。
A for
loop with an omitted second expression loops forever because the specification of for
statement says so. 一个
for
与省略第二表达式循环,循环永远,因为规范for
声明是这样说的。 Ie it is a dedicated feature specific to for
alone, not something more generic. 即它是专门
for
单独的专用功能,而不是更通用的功能。
Additionaly (a terminological nitpick) only the second expression is really a condition . 另外(一个术语的挑剔)只有第二个表达才是真正的条件 。 The first and the third are not really "conditions".
第一个和第三个不是真正的“条件”。
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