[英]Selecting max value for a column in Oracle
I have a table which has data like this 我有一张桌子,上面有这样的数据
id test_val type_cd
#-------------------------
101 TEST22 M
102 TEST23 M
103 TEST01 M
103 TEST01 H
104 TEST02 M
104 TEST02 H
105 TEST03 H
I would like to fetch the max(id) for each type_cd and its corresponding test_val in a single row output as below. 我想在单行输出中为每个type_cd及其对应的test_val获取max(id),如下所示。
The expected output is: 预期的输出是:
M_id M_Test_Val H_id H_Test_Val
#-----------------------------------
104 TEST02 105 TEST03
If I have to fetch only the max(id) for each type_cd I'll have my query like this 如果我只需要获取每个type_cd的max(id),我将得到这样的查询
select max(case when type_cd='M' then max(id) else null end) as M_id,
max(case when type_cd='H' then max(id) else null end) as H_id
from t1
group by type_cd;
I'm not sure how to get the test_val for the max(id)
for each type_cd
. 我不确定如何为每个type_cd
获取max(id)
的test_val。
This is the sort of scenario where analytic functions come into their own.... 这是分析功能发挥作用的一种情况。
select type_cd
, id as max_id
, test_val
from (
select type_cd
, id
, test_val
, rank () over (partition by type_cd order by id desc) as rank_id
from your_table
)
where rank_id = 1
/
edit 编辑
The above query doesn't satisfy your need for a single row. 上面的查询无法满足您对单行的需求。 Slotting that query into a CTE like this ought to do it... 像这样将查询插入CTE应该可以做到...
with subq as
( select type_cd
, id as max_id
, test_val
from (
select type_cd
, id
, test_val
, rank () over (partition by type_cd
order by id desc) as rank_id
from your_table
)
where rank_id = 1 )
select m.id as m_id
, m.test_val as m_test_val
, h.id as h_id
, h.test_val as h_test_val
from ( select * from subq where type_cd = 'M') m
join ( select * from subq where type_cd = 'H') h
/ /
I wrote the code as below and it works as expected. 我写了下面的代码,它可以按预期工作。
select max(case when type_cd='M' then id else null end) as m_id,
max(case when type_cd='M' then test_val else null end) as m_test_val,
max(case when type_cd='H' then id else null end) as h_id,
max(case when type_cd='M' then test_val else null end) as h_test_val
from
( select type_cd ,
id ,
test_val ,
rank () over (partition by type_cd order by id desc) as rank_id
from your_table )
where rank_id = 1;
Not sure if this is the optimal way. 不知道这是否是最佳方法。 But works just as I want it to. 但是可以按照我想要的方式工作。
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