[英]Find an element in a list of tuples
I have a list 'a'我有一个列表“a”
a= [(1,2),(1,4),(3,5),(5,7)]
I need to find all the tuples for a particular number.我需要找到特定数字的所有元组。 say for 1 it will be
说 1 它将是
result = [(1,2),(1,4)]
How do I do that?我怎么做?
If you just want the first number to match you can do it like this:如果您只想匹配第一个数字,您可以这样做:
[item for item in a if item[0] == 1]
If you are just searching for tuples with 1 in them:如果您只是搜索其中包含 1 的元组:
[item for item in a if 1 in item]
There is actually a clever way to do this that is useful for any list of tuples where the size of each tuple is 2: you can convert your list into a single dictionary.实际上有一种聪明的方法可以做到这一点,它对于每个元组大小为 2 的任何元组列表都很有用:您可以将列表转换为单个字典。
For example,例如,
test = [("hi", 1), ("there", 2)]
test = dict(test)
print test["hi"] # prints 1
Read up on List Comprehensions阅读列表理解
[ (x,y) for x, y in a if x == 1 ]
Also read up up generator functions and the yield
statement.还要阅读生成器函数和
yield
语句。
def filter_value( someList, value ):
for x, y in someList:
if x == value :
yield x,y
result= list( filter_value( a, 1 ) )
[tup for tup in a if tup[0] == 1]
for item in a:
if 1 in item:
print item
The filter
function can also provide an interesting solution: filter
函数还可以提供一个有趣的解决方案:
result = list(filter(lambda x: x.count(1) > 0, a))
which searches the tuples in the list a
for any occurrences of 1
.它在列表
a
搜索元组中出现的任何1
。 If the search is limited to the first element, the solution can be modified into:如果搜索仅限于第一个元素,则解决方案可以修改为:
result = list(filter(lambda x: x[0] == 1, a))
Using filter function:使用过滤功能:
>>> def get_values(iterables, key_to_find):
return list(filter(lambda x:key_to_find in x, iterables)) >>> a = [(1,2),(1,4),(3,5),(5,7)] >>> get_values(a, 1) >>> [(1, 2), (1, 4)]
>>> [i for i in a if 1 in i]
[(1, 2), (1, 4)]
Or takewhile
, ( addition to this, example of more values is shown ):或
takewhile
,(除此之外,还显示了更多值的示例):
>>> a= [(1,2),(1,4),(3,5),(5,7),(0,2)]
>>> import itertools
>>> list(itertools.takewhile(lambda x: x[0]==1,a))
[(1, 2), (1, 4)]
>>>
if unsorted, like:如果未排序,例如:
>>> a= [(1,2),(3,5),(1,4),(5,7)]
>>> import itertools
>>> list(itertools.takewhile(lambda x: x[0]==1,sorted(a,key=lambda x: x[0]==1)))
[(1, 2), (1, 4)]
>>>
if you want to search tuple for any number which is present in tuple then you can use如果要搜索元组中存在的任何数字的元组,则可以使用
a= [(1,2),(1,4),(3,5),(5,7)]
i=1
result=[]
for j in a:
if i in j:
result.append(j)
print(result)
You can also use if i==j[0] or i==j[index]
if you want to search a number in particular index如果要在特定索引中搜索数字,也可以使用
if i==j[0] or i==j[index]
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