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如何在Objective-C中将对象设置为接口?

[英]How to set a object to an interface in Objective-C?

我想知道如何在Objective-C中为接口(即@protocol)创建对象?

It is not very clear what do you want to get. 您还不确定要获得什么。

If you want to define a class that conforms to a protocol you write: 如果要定义符合协议的类,请编写:

    @interface MyClass: ParentClass <MyProtocol1, MyProtocol2,...>

If you want to define an object that must be an instance of some class that confirms to a protocol you can write: 如果要定义一个对象,该对象必须是某个可以确认协议的类的实例,则可以编写:

   id<MyProtocol> myObject;

If you want to obtain Protocol object by name you can use 如果要按名称获取协议对象,可以使用

Protocol *objc_getProtocol(const char *name)

function. 功能。 I don't know if you can create Protocol in run-time though. 我不知道您是否可以在运行时创建协议。

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