将C ++对象（尤其是stl容器）移动到特定的内存位置

Question

I am working with a memory manager that, on occasion, wants to defragment memory. Basically, I will go through a list of objects allocated by the memory manager and relocate them:

class A {
  SomeClass* data; // This member is allocated by the special manager
};

for(... each instance of A ...) 
    a.data = memory_manager.relocate(a.data);

memory_manager.relocate() will memcpy() the contents of data to a new location, and return the pointer.

Although it's generally not idiomatic to memcpy() C++ classes, it seems to be a useful solution in this case, considering that I control the implementation of the (few) classes that will be used with the memory manager.

The problem is that one of those classes uses std::map , which is an opaque class as far as I am concerned. I certainly don't imagine I can memcpy() it. I may not be able to use std::map in any case. For all I know it could allocate several pieces of memory.

The best workaround I can think of is simple enough. Due to the fact that the fragmented memory manager will put new allocations at more beneficial locations, all I need to do is allocate it anew and then delete the old:

for(... each instance of A ...) {
    stl::map<something>* tmp = a.the_map;
    a.the_map = new stl::map<something>(tmp);
    delete tmp;
}

In any case, this lead me to wonder:

Does C++ have semantics or idioms to move/copy an object into a specific memory location?

Is it possible to move the contents of an stl container to a specific memory location?

Edit: Although I didn't point it out, I would obviously pass an allocator parameter to std::map. Based on the informative answers I got, I realize the workaround I posted in my initial question would probably be the only way to reduce fragmentation. By using the map's copy constructor (and the allocator template parameter), all memory used by the map would be properly re-allocated.

As a comment pointed out, this is mostly a theoretical problem. Memory fragmentation is rarely something to worry about.

Answer 1

Everytime you insert a new key,value pair the map will allocate a node to store it. The details of how this allocation takes place are determined by the allocator that the map uses.

By default when you create a map as in std::map<K,V> the default allocator is used, which creates nodes on the heap (ie, with new / delete ).

You don't want that, so you'll have to create a custom allocator class that creates nodes as dictated by your memory manager.

Creating an allocator class is not trivial. This code shows how it can be done, you'll have to adapt it to your own needs.

Once you have your allocator class (let's say you call it MemManagerAllocator ) you'll have to define your map as std::map<K, V, MemManagerAllocator> and then use it like you would use a regular map.

Personally, I would need to have a really bad problem of memory fragmentation to go into all that trouble.

Answer 2

The contents of a C++ object will be scattered around the heap. A STL object for example a container or string etc might store its meta-data on your stack (if you don't put it in dynamic memory) ... however the contents are scattered arround the heap.

It will be a hard task to keep track of all the elements of an object, and all the references to these elements. The language has to provide some form of "hooks" or events to enable tracking the relationships between chunks of memories.

So no, you can't just memcpy a arbitrary STL object.

Afaik overriding new is not a panacea, it is a "process global" concept so trying to localize the news to a thread-object-allocation pair is not possible. And this localization would enable you to group the memory together.

You could write your own containers that used a custom memory allocator explicitly (explicit because your provide the necessary object identity information), and there are some custom allocators out there.

Answer 3

You could use placement new?

void* adress = new void[size_of(*old_map_ptr)]; // or wherever you want it in your memory
map<type> new_map* = new (adress) map<type>(*old_map_ptr);
delete old_map_ptr;

Answer 4

不，C ++本身只管理内存，但你可以通过实现std :: map :: allocator来帮助stl实现它，它会一直这样做，所以你不需要memcpy它。

Answer 5

You did not mention which platform you are coding for or if that is allowed to matter. But in Linux and the GCC, the C++ default allocator is implemented with malloc .

malloc can be overridden and replaced with your own internal allocator.

I would implement this malloc as follows:

in the general case, just defer to original malloc . Whenever you want to, you can change the behavior of the malloc function to return pointers to this special memory area you have prepared.

So, before creating this particular std::map you would give your malloc a hint. (Through a global variable or some other means of communication.)

Update: alemjerus suggested implementing std::map::allocator which is a much cleaner way on the same theme, also platform agnostic.

Answer 6

You can use placement new to define where the base std::map object lives. But the majority of the space will be allocated on the heap, by std::map.