正则表达式从推文中提取@name符号

Question

I would like to use regular expression to extract only @patrick @michelle from the following sentence:

@patrick  @michelle we having diner @home tonight do you want to join?

Note: @home should not be include in the result because, it is not at beginning of the sentence nor is followed by another @name .

Any solution, tip, comments will be really appreciated.

Answer 1

/(?:(?:@\S+\s+)+|^)@\S+/g

It first matches either an "@" followed by many non-space characters, or the start of line, and then matches another "@" followed by many non-space characters.

Note that it's common in Twitter that @name is preceded by RT , appears in the middle or end of the tweet eg http://twitter.com/ceetee/statuses/9874073403 . Basically you can't distinguish whether a @name is really a name just using RegEx or even a parser. The best bet is to check if http://twitter.com/name 404 or not.

Answer 2

Well, at first I thought this failed because I looked at the groups that are returned:

>>> tw = re.compile(r"^((@\w*)\s+)*")
>>> tw.findall(tweet)
[('@michelle ', '@michelle')]
>>> tw.match(tweet).groups()
('@michelle ', '@michelle')

Note that the groups only keep the last value for any group in the re. But if you just grab group(), then you get the whole matched string:

>>> tw.match(tweet).group()
'@patrick  @michelle '

For grins, I'll try pyparsing:

>>> from pyparsing import Word, printables, OneOrMore
>>> atName = Word("@",printables)
>>> OneOrMore(atName).parseString(tweet).asList()
['@patrick', '@michelle']

Answer 3

Try this regular expression:

/^\s*@(\w+)\s+@(\w+)/

\\s denotes whitespace characters and \\w word characters.

Answer 4

As long as it starts with an @ and continues with those this will do it I tested it in poweshell so some regex engines are a bit different. This should also catch n names at the beginning of the line

"^((@\\w+)\\s)+"

Answer 5

也许像这样，尽管您必须将匹配组中的任何内容都在空白处拆分以提取多个ID。

/^\s*(@\w+\s+)*\s+.*$/

Answer 6

You have tagged your post c#, so I assume you can use the .NET Regex imnplementation. Using .NET, the following Regex will do:

(?<![^@]\w+\s+)(@\w+)

This will match any words starting with @, that do not have a word without @ before them. Note that "dinner @home @8pm" will still break it, though.

See here for more details.

Answer 7

for PHP

/^\s*@(\w+)\s+@(\w+)/

Thanks KennyM

in python

msg = '@patrick  @michelle we having diner @home tonight do you want to join?'
import re
re.findall('(?:(?:@\S+\s+)+|^)@\S+', msg)

This works with 1 or n @name at the beginning of the sentence.

Thank you all for the quick replies.

Answer 8

In Perl, you can exploit the /g match-more-than-once modifier combined with the \\G zero-width where-we-left-off assertion and list context, thus:

my $str = '@patrick  @michelle we having diner @home tonight do you want to join?';
my @matches = ($str =~ m/\G(\@\w+)\s*/g);

print join(', ', @matches) . "\n";

This should be robust across any number of initial @-strings.

Answer 9

For Python check out: http://github.com/BonsaiDen/AtarashiiFormat
It will also give you the links and the tags.

And beware of using a simple regex, you will end up with a big mess, as I did before I converted the Twitter Text Java Library.

Answer 10

For C# I would do as follows:

@([A-Za-z0-9-_&;]+)