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如何从 unix c 中的 struct addrinfo 获取端口号

[英]How to get the port number from struct addrinfo in unix c

I need to send some data to a remote server via UDP in a particular port and get receive a response from it.我需要通过特定端口中的 UDP 将一些数据发送到远程服务器并从它接收响应。 However, it is blocking and I do not get any response.但是,它正在阻塞,我没有得到任何响应。 I need to check if the addrinfo value that I get from the getaddrinfo(SERVER_NAME, port, &hints, &servinfo) is correct or not.我需要检查从getaddrinfo(SERVER_NAME, port, &hints, &servinfo)获得的 addrinfo 值是否正确。

How do I get the port number from this data structure?如何从这个数据结构中获取端口号?

I know inet_ntop(p->ai_family, get_in_addr((struct sockaddr *)p->ai_addr), s, sizeof s) gives me server IP address.我知道inet_ntop(p->ai_family, get_in_addr((struct sockaddr *)p->ai_addr), s, sizeof s)给了我服务器 IP 地址。 (I am using the method in Beej's guide.) (我正在使用 Beej 指南中的方法。)

You do something similar to what Beej's get_in_addr function does:你做一些类似于 Beej 的 get_in_addr 函数所做的事情:

// get port, IPv4 or IPv6:
in_port_t get_in_port(struct sockaddr *sa)
{
    if (sa->sa_family == AF_INET)
        return (((struct sockaddr_in*)sa)->sin_port);

    return (((struct sockaddr_in6*)sa)->sin6_port);
}

Also beware of the #1 pitfall dealing with port numbers in sockaddr_in (or sockaddr_in6 ) structures: port numbers are always stored in network byte order .还要注意在sockaddr_in (或sockaddr_in6 )结构中处理端口号的#1 陷阱:端口号总是以网络字节顺序存储。

That means, for example, that if you print out the result of the get_in_port() call above, you need to throw in a ntohs() :这意味着,例如,如果你打印出上面get_in_port()调用的结果,你需要抛出一个ntohs()

printf("port is %d\n", ntohs(get_in_port((struct sockaddr *)p->ai_addr)));

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