在python中使用os.system来运行带参数的程序

Question

How do I get python to run sudo openvpn --cd /etc/openvpn --config client.ovpn

I'm trying the following at the minute without success

vpnfile2 = '/etc/init.d/openvpn'
cfgFile = 'client.ovpn'

os.system('sudo \"" + vpnFile2 + "\" --cd \"" + vpnpath + "\" --config \"" + cfgFile + "\"')

Answer 1

use the subprocess module

import subprocess
subprocess.call(['sudo', vpnFile2, '--cd', vpnpath, '--config', cfgFile])

Answer 2

This question has been posted awhile ago, but if someone comes across this (like me), there is another way to get privileges using the os.system method ..

It will only work if you are running this in a GUI environment. You can simply try to call it with 'gksu' or ('kdesu' or 'kdesudo'), it would look like this in a gnome session:

import os
vpnfile2 = '/etc/init.d/openvpn'
cfgFile = 'client.ovpn'

os.system('gksu \"" + vpnFile2 + "\" --cd \"" + vpnpath + "\" --config \"" + cfgFile + "\"')

The prompt works, but I have not tested it to work with your code.

Answer 3

If there is some reason you want to use os.system, instead of subprocess, I usually wash it through bash, so os.system('''sudo bash -c "command to run"''') (Or sh or whatever shell you have). It processes the arguments better in many cases.