[英]Comparing two List<MyClass> in C#
I have a class called 我有一个叫做的课
MyClass
This class inherits IEquatable and implements equals the way I need it to. 这个类继承IEquatable并实现等于我需要它的方式。 (Meaning: when I compare two MyClass tyupe objects individually in code, it works)
(含义:当我在代码中单独比较两个MyClass tyupe对象时,它可以工作)
I then create two List: 然后我创建两个List:
var ListA = new List<MyClass>();
var ListB = new List<MyClass>();
// Add distinct objects that are equal to one another to
// ListA and ListB in such a way that they are not added in the same order.
When I go to compare ListA and ListB, should I get true? 当我去比较ListA和ListB时,我应该得到真的吗?
ListA.Equals(ListB)==true; //???
Try the following 请尝试以下方法
ListA.SequenceEquals(ListB);
SequenceEquals is an extension method available on the Enumerable
class. SequenceEquals是
Enumerable
类上可用的扩展方法。 This is available by default in C# 3.5 projects as it comes with System.Linq 这在C#3.5项目中是可用的,因为它随System.Linq一起提供
To answer your question, no, you should not get true. 要回答你的问题,不,你不应该成真。
List
and List<T>
do not define .Equals, so they inherit Object.Equals, which checks the following: List
和List<T>
不定义.Equals,因此它们继承Object.Equals,它检查以下内容:
public static bool Equals(object objA, object objB)
{
return ((objA == objB) || (((objA != null) && (objB != null)) && objA.Equals(objB)));
}
And objA.Equals(objB)
is virtual. 而
objA.Equals(objB)
是虚拟的。 If I recall correctly, the default implementation just checks for reference equality (pointing to the same object in memory), so your code would return false. 如果我没记错的话,默认实现只是检查引用相等性(指向内存中的同一个对象),因此你的代码将返回false。
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