我如何在python中将整数转换为'二进制'

Question

In Ruby i do so

asd = 123
asd = '%b' % asd # => "1111011"

Answer 1

in Python >= 2.6 with bin() :

asd = bin(123) # => '0b1111011'

To remove the leading 0b you can just take the substring bin(123)[2:] .

bin(x)
Convert an integer number to a binary string. The result is a valid Python expression. If x is not a Python int object, it has to define an __index__() method that returns an integer.

New in version 2.6.

Answer 2

you can also do string formatting, which doesn't contain '0b' :

>>> '{:b}'.format(123)            #{0:b} in python 2.6
'1111011'

Answer 3

bin() works, as Felix mentioned. For completeness, you can go the other way as well.

>>> int('01101100',2)
108
>>> bin(108)
'0b1101100'
>>> bin(108)[2:]
'1101100'