如何获取客户端程序的本地TCP端口和IP地址？

Question

I'm prepping for a simple work project and am trying to familiarize myself with the basics of socket programming in a Unix dev environment. At this point, I have some basic server side code and client side code setup to communicate. Currently, my client code successfully connects to the server code and the server code sends it a test message, then both quit out. Perfect! That's exactly what I wanted to accomplish. Now I'm playing around with the functions used to obtain info about the two environments (server and client). I'd like to obtain the local IP address and dynamically assigned TCP port of the client. The function I've found to do this is getsockname() ...

//setup the socket
if ((sockfd = socket(p->ai_family, p->ai_socktype, p->ai_protocol)) == -1) 
{
   perror("client: socket");
   continue;
}

//Retrieve the locally-bound name of the specified socket and store it in the sockaddr structure
sa_len = sizeof(sa);
getsock_check = getsockname(sockfd,(struct sockaddr *)&sa,(socklen_t *)&sa_len) ;
if (getsock_check== -1) {
    perror("getsockname");
    exit(1);
}

printf("Local IP address is: %s\n", inet_ntoa(sa.sin_addr));
printf("Local port is: %d\n", (int) ntohs(sa.sin_port));

but the output is always zero...

Local IP address is: 0.0.0.0
Local port is: 0

does anyone see anything I might be or am definitely doing wrong?

Thanks so much in advance for all your help!

Answer 1

From the looks of your code you are not doing connect or accept on the socket. Until you have done this the data you get from getsockname is undefined.

Answer 2

在你调用connect（）之前，我认为你不能在这个上下文中有意义地调用getsockname - 内核不会将它绑定到特定端口，直到它需要（或被告知明确地这样做），并且本地地址是根据路由表选择的，因此也是目的地。