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Unix substr在shell脚本中?

[英]Unix substr in shell script?

I have a string like sample.txt.pgp and I want to return sample.txt in a shell script (but, the string length will vary, so, basically all of the characters before the ".pgp"). 我有一个像sample.txt.pgp这样的字符串,我想在shell脚本中返回sample.txt(但是,字符串的长度会有所不同,因此,基本上所有在“ .pgp”之前的字符)。 Is there a substr function? 有substr函数吗? Like, if I did substr('sample.txt.pgp', -4, 0) , is it supposed to return sample.txt? 就像,如果我做了substr('sample.txt.pgp', -4, 0) ,它应该返回sample.txt吗? Right now it isn't, so I'm wondering if I have the syntax wrong, or maybe substr isn't a function? 现在不是,所以我想知道语法是否错误,或者substr不是函数吗?

a='sample.txt.pgp'
echo ${a%.*}   # sample.txt (minimal match)
echo ${a%%.*}  # sample     (maximal match)

You can use basename : 您可以使用basename

$ basename sample.txt.pgp .pgp
sample.txt

Use backticks or $() to put the result in a variable if you want: 如果需要,请使用反引号或$()将结果放入变量中:

$ FILE=sample.txt.pgp
$ VARIABLE=$(basename "$FILE" .pgp)
$ echo $VARIABLE
sample.txt

filename sample.txt.pgp returns sample.txt, I believe. 我相信, filename sample.txt.pgp返回sample.txt。 (use backticks) (使用反引号)

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