Drupal-视图中选定节点的突出显示

Question

Drupal Question:

Does anyone have a method of using Views and highlighting a selected/current node.

So for example:

I have a list of articles under a heading:

2009 Articles

Dog Training

Cat Cleaning

Snake Wrangling

The 3 articles are made from the view (ie: latest articles from 2009)... as the user makes new articles, they are automatically added into this view by title.

I now need to find a way, that if a user clicks on say CAT CLEANING.... and the cat cleaning article appears, the CAT CLEANING in the view becomes bold (or some CSS indication it's the current article.)

I know this is pretty easy with MENU's, But I don't want to force a user to add new articles into a menu.

Thanks alot, JD

Answer 1

1. In the Context Filters, add "Global:null" and select "Get content ID from URL"
2. Add a NID field and set "Exclude from display"
3. Add a Mathematic field who evaluate difference between the both NID : "!1-[nid]"and set "Exclude from display"
4. Add a class to the field to highlight as "active[expression]" where active0 is the class of the current node.

There is the video tutorial to achieve that: http://youtu.be/0uSfuVmO6zk

Answer 2

您可以覆盖正在使用的任何Views模板（通过单击“视图”编辑页面上的“主题：信息”链接来执行此操作），并基本上说“如果此节点的链接与当前查看的路径相同，则添加一个'当前的课程”。

Answer 3

Here is what you need to do:

1. Look up the class of the view list item (eg Dog training) using Firebug
2. Add CSS for the view list item manually in the theme folder or using something more convenient like the css injector module

3. The CSS will be something like this

   .view-name .view-name-of-field-here a:active {text-decoration: underline; color: red}

Here we are using the "active" CSS pseudo class to color and underline the link if the URL in the view list item is the same URL as the web page.