如何编写“从（表）中选择（全部）”，其中“发帖= $发帖，除此发帖？”（Mysql）

Question

I want to write a Mysql statement that selects all from a table(posting) where title is like $title except for the title of $title. Basically I want to display all related posting of a certain posting. I want the query to select all the postings in the table that has the title name in the title OR detail. But I don't want the posting to display in the related postings.

//pseudocode
$query="Select * From posting Where title,detail, like %$title% except $title";

how do I write the except part?

Answer 1

This is the code you need, although it will be better if you have the current post id and just have something like WHERE id != " . (int)$current_post_id . "

$title = mysql_real_escape_string($title);

$sql = "
    SELECT *
    FROM posting
    WHERE
        title LIKE '%" . $title . "%' AND
        detail LIKE '%" . %title . "%' AND
        title != " . $title . "
    ";

---

Here is the ID version, way better :)

$title = mysql_real_escape_string($title);

$sql = "
    SELECT *
    FROM posting
    WHERE
        title LIKE '%" . $title . "%' AND
        detail LIKE '%" . %title . "%' AND
        id != " . (int)$post_id . "
    ";

Answer 2

EDIT: If you want LIKE '%$title%' AND != '$title' then:

SELECT * FROM posting 
WHERE title LIKE '%$title%' AND detail LIKE '%$title%' AND title !=  '$title';

else

SELECT * FROM posting 
WHERE title LIKE '%$title%' AND detail LIKE '%$title%' AND title NOT LIKE '%$title%';

Are you sure that's correct? LIKE '%$title%' AND NOT LIKE '%$title%' is a contradiction.