[英]Question About SQL Query
I am using the below statement to generate age of a person in Oracle SQL and my question is below. 我正在使用以下语句在Oracle SQL中生成人员年龄,而我的问题如下。
SELECT TO_NUMBER(TO_CHAR(CURRENT_DATE,'YYYY'))-TO_NUMBER(TO_CHAR(BIRTH_DATE,'YYYY'))
FROM NAME WHERE NAME_ID =NAME_ID
This statement is only correct upto so far that I need a statement which could count months and even days in order to get the age. 到目前为止,这句话是正确的,因此我需要一个可能要数月甚至数天才能得出年龄的声明。
Googling for 'oracle get age from dob' returns several answers 谷歌搜索“ oracle从dob获得年龄”返回几个答案
select trunc((months_between(sysdate, dob))/12) age
from name;
looks like a good solution (trunc is optional) and 看起来是一个很好的解决方案(trunc是可选的),并且
select to_number(to_char(sysdate,'YYYY')) - to_number(to_char(bth_date,'YYYY')) +
decode(sign(to_number(to_char(sysdate,'MMDD')) -
to_number(to_char(bth_date,'MMDD'))),-1,-1,0) age
from name;
is also correct. 是正确的。
You could use the EXTRACT function like 您可以使用EXTRACT函数,例如
SELECT EXTRACT( YEAR FROM( CURRENT_DATE - BIRTH_DATE )) FROM ...
Substitute YEAR by whatever you need. 用您需要的任何内容替代YEAR。
/edit I think I misread. / edit我想我读错了。 If you need higher precisions maybe Intervals could help ( http://blagispat.blogspot.com/2007/11/heres-short-article-on-using-intervals.html ).
如果您需要更高的精度,间隔可能会有所帮助( http://blagispat.blogspot.com/2007/11/heres-short-article-on-using-intervals.html )。 (Sry but new users can only post one hyperlink).
(很抱歉,新用户只能发布一个超链接)。
SELECT EXTRACT( YEAR FROM( CURRENT_DATE - BIRTH_DATE) YEAR TO MONTH ) FROM ...
or 要么
SELECT EXTRACT( DAY FROM( CURRENT_DATE - BIRTH_DATE) DAY TO SECOND ) FROM ...
which returns days. 返回天数。
Oracle supports arithmetic operations directly on DATE
columns: Oracle直接在
DATE
列上支持算术运算:
SELECT SYSDATE - BIRTH_DATE FROM NAME WHERE NAME_ID =NAME_ID
The result here will be a number which expresses the difference in days. 这里的结果将是一个表示天数差异的数字。
If you want it in months, use this: 如果您想在几个月内使用它,请使用以下命令:
SELECT MONTHS_BETWEEN(SYSDATE, BIRTH_DATE) FROM NAME...
If you want it in years, divide MONTHS_BETWEEN
by 12. 如果您希望以年为单位,
MONTHS_BETWEEN
除以12。
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